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Stain Hardwood Floors cost in Cheyenne

How Much Does Stain Hardwood Floors Cost in Cheyenne, Wyoming?

Sand an existing hardwood floor to bare wood, apply a stain color and 2-3 coats of finish, per sq ft.

Stain Hardwood Floors in Cheyenne, Wyoming typically costs $3.34 to $7.63 per sq ft as of 2026. Prices reflect local labor and material rates. Use our calculator below for a detailed, ZIP-code-adjusted estimate.

Stain Hardwood Floors in Cheyenne, Wyoming

$3.34 – $7.63

per sq ft

Prices in Cheyenne are 4.0% lower than the national average for stain hardwood floors.

National average: $3.50 – $8 per sq ft

What you get at each price level

  • Basic

    $2.84 – $6.48 per sq ft

    Floor sanded to bare wood, stain applied, two coats of oil-based polyurethane

  • Standard

    $3.34 – $7.63 per sq ft

    Floor sanded through three grits, water-popped for even color, stain, three coats of polyurethane

  • Premium

    $4.17 – $9.54 per sq ft

    Sanded and screened, water-popped, stain, sealer and three coats of commercial-grade waterborne finish

Cost Breakdown in Cheyenne

ComponentCategoryPrice RangeUnit
Materialsmaterial$1.49 – $3.43sq ft
Laborlabor$1.19 – $2.69sq ft
Supplies & Othersupplies$0.40 – $0.92sq ft
Equipment & Disposalequipment$0.26 – $0.59sq ft
Prices adjusted for Cheyenne local market conditions.

Stain Hardwood Floors photo examples

Cost Factors in Cheyenne, Wyoming

What Affects Pricing

  • Materials ($1.57-$3.61 per square foot)
  • Labor ($1.24-$2.80 per square foot)
  • Supplies & Other ($0.42-$0.97 per square foot)
  • Equipment & Disposal ($0.27-$0.62 per square foot)

Local Price Adjustments

Material costs5.0% below avg
Labor costs4.0% below avg

Frequently Asked Questions

References

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