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Stain Hardwood Floors cost in Columbus

How Much Does Stain Hardwood Floors Cost in Columbus, Ohio?

Sand an existing hardwood floor to bare wood, apply a stain color and 2-3 coats of finish, per sq ft.

Stain Hardwood Floors in Columbus, Ohio typically costs $3.45 to $7.88 per sq ft as of 2026. Prices reflect local labor and material rates. Use our calculator below for a detailed, ZIP-code-adjusted estimate.

Stain Hardwood Floors in Columbus, Ohio

$3.45 – $7.88

per sq ft

Prices in Columbus are in line with the national average for stain hardwood floors.

National average: $3.50 – $8 per sq ft

What you get at each price level

  • Basic

    $2.93 – $6.70 per sq ft

    Floor sanded to bare wood, stain applied, two coats of oil-based polyurethane

  • Standard

    $3.45 – $7.88 per sq ft

    Floor sanded through three grits, water-popped for even color, stain, three coats of polyurethane

  • Premium

    $4.31 – $9.86 per sq ft

    Sanded and screened, water-popped, stain, sealer and three coats of commercial-grade waterborne finish

Cost Breakdown in Columbus

ComponentCategoryPrice RangeUnit
Materialsmaterial$1.48 – $3.39sq ft
Laborlabor$1.33 – $3sq ft
Supplies & Othersupplies$0.39 – $0.91sq ft
Equipment & Disposalequipment$0.25 – $0.58sq ft
Prices adjusted for Columbus local market conditions.

Stain Hardwood Floors photo examples

Cost Factors in Columbus, Ohio

What Affects Pricing

  • Materials ($1.57-$3.61 per square foot)
  • Labor ($1.24-$2.80 per square foot)
  • Supplies & Other ($0.42-$0.97 per square foot)
  • Equipment & Disposal ($0.27-$0.62 per square foot)

Local Price Adjustments

Material costs6.0% below avg
Labor costs7.0% above avg

Labor costs in Columbus run proportionally higher than materials, which may favor material-heavy solutions.

Frequently Asked Questions

References

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