Basic
$1.62 – $4.05 per sq ft
Floor covering torn out down to the subfloor up to the cabinets, debris hauled away, broom-swept

Tear out existing kitchen floor covering (vinyl, laminate, wood or tile) down to the subfloor and dispose of debris.
Remove Kitchen Floor in Salt Lake City, Utah typically costs $1.91 to $4.77 per sq ft as of 2026. Prices reflect local labor and material rates. Use our calculator below for a detailed, ZIP-code-adjusted estimate.
Prices in Salt Lake City are 5.0% lower than the national average for remove kitchen floor.
National average: $2 – $5 per sq ft
$1.62 – $4.05 per sq ft
Floor covering torn out down to the subfloor up to the cabinets, debris hauled away, broom-swept
$1.91 – $4.77 per sq ft
Floor covering and underlayment removed, staples and nails pulled, cabinet toe kicks protected, debris hauled
$2.38 – $5.96 per sq ft
Dust barriers set, flooring removed, adhesive and thinset scraped off, subfloor vacuumed, debris hauled
| Component | Category | Price Range | Unit |
|---|---|---|---|
| Materials | material | $0.86 – $2.16 | sq ft |
| Labor | labor | $0.66 – $1.65 | sq ft |
| Supplies & Other | supplies | $0.23 – $0.58 | sq ft |
| Equipment & Disposal | equipment | $0.15 – $0.38 | sq ft |
Connect with local remove kitchen floor contractors in Salt Lake City for personalized quotes based on your specific project.