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Remove Kitchen Floor cost in Salt Lake City

How Much Does Remove Kitchen Floor Cost in Salt Lake City, Utah?

Tear out existing kitchen floor covering (vinyl, laminate, wood or tile) down to the subfloor and dispose of debris.

Remove Kitchen Floor in Salt Lake City, Utah typically costs $1.91 to $4.77 per sq ft as of 2026. Prices reflect local labor and material rates. Use our calculator below for a detailed, ZIP-code-adjusted estimate.

Remove Kitchen Floor in Salt Lake City, Utah

$1.91 – $4.77

per sq ft

Prices in Salt Lake City are 5.0% lower than the national average for remove kitchen floor.

National average: $2 – $5 per sq ft

What you get at each price level

  • Basic

    $1.62 – $4.05 per sq ft

    Floor covering torn out down to the subfloor up to the cabinets, debris hauled away, broom-swept

  • Standard

    $1.91 – $4.77 per sq ft

    Floor covering and underlayment removed, staples and nails pulled, cabinet toe kicks protected, debris hauled

  • Premium

    $2.38 – $5.96 per sq ft

    Dust barriers set, flooring removed, adhesive and thinset scraped off, subfloor vacuumed, debris hauled

Cost Breakdown in Salt Lake City

ComponentCategoryPrice RangeUnit
Materialsmaterial$0.86 – $2.16sq ft
Laborlabor$0.66 – $1.65sq ft
Supplies & Othersupplies$0.23 – $0.58sq ft
Equipment & Disposalequipment$0.15 – $0.38sq ft
Prices adjusted for Salt Lake City local market conditions.

Cost Factors in Salt Lake City, Utah

What Affects Pricing

  • Materials ($0.90-$2.25 per square foot)
  • Labor ($0.70-$1.75 per square foot)
  • Supplies & Other ($0.24-$0.60 per square foot)
  • Equipment & Disposal ($0.16-$0.40 per square foot)

Local Price Adjustments

Material costs4.0% below avg
Labor costs6.0% below avg

Frequently Asked Questions

References

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